During a code review, I was asked why I wrote the following C code:
double dval = ...; uint16_t uval = (uint16_t) MAX(0, MIN(dval, UINT16_MAX));
If I am going to store the value unsigned, why do I need the
MIN values? Won’t the cast operator take care of this for us? I’ll give you a hint - assume you can’t trust the double. Still stumped?
The cast operators are inherently unsafe if the input is out of bounds of what can be stored in the destination. They can do more than just clip the value at the maximum.
double dval = 1000000000000; int ival = (int)dval; unsigned int uval = (unsigned int)(int)dval; unsigned int uval2 = (unsigned int)dval;
What do you think ival, uval, and uval2 will be (on a Microsoft compiler)? The answer may surprise you.
ival = -2147483648 uval = 2147483648 uval2 = 3567587328
We ended up with a negative value for the integer, a positive value for the first unsigned value, and a random positive value for the second unsigned integer. None of the values makes any sense. If you are casting between types and you don’t know if the value is in range, then you must first bound the input with